更新时间:2022-10-15 20:48:17
There is no built-in function or method that can do this. However, you could easily define your own.
def common_entries(*dcts):
for i in set(dcts[0]).intersection(*dcts[1:]):
yield (i,) + tuple(d[i] for d in dcts)
This builds on the "manual method" you provide, but, like zip
, can be used for any number of dictionaries.
>>> da = {'a': 1, 'b': 2, 'c': 3}
>>> db = {'a': 4, 'b': 5, 'c': 6}
>>> list(common_entries(da, db))
[('c', 3, 6), ('b', 2, 5), ('a', 1, 4)]
When only one dictionary is provided as an argument, it essentially returns dct.items()
.
>>> list(common_entries(da))
[('c', 3), ('b', 2), ('a', 1)]