更新时间:2022-02-26 22:50:06
嗨。
你不能在26号线上正确地关闭你的弦。
这就是你得到这个的原因错误。
此外,关闭该代码中的一个巨大的安全漏洞。
不要将用户输入直接放入SQL查询...或任何东西, 对于这个问题。
在使用它之前总是验证它并消毒它。
mysql_real_escape_query 功能在这里非常有用。
查看 SQL注入。解释为什么这么重要。
Hi.
You don''t close your string properly on line #26.
That''s why you get this error.
Also, to close a huge security hole in that code.
Don''t put user input directly into SQL queries... or anything, for that matter.
Always validate it and sanitize it before using it.
The mysql_real_escape_query function is extremely helpful here.
Check out SQL Injection in the manual. Explains why this is so important.
我如何结束第26行?我试过删除分号和使用)代替},我仍然得到相同的结果。我不确定接下来要尝试什么。
How would I end line 26? I have tried removing the semi-colon and using ) instead of } and I still keep getting the same result. I am not really sure what to try next.
在分号前用双引号关闭字符串。
字符串应该在引号中包含,但你只打开字符串,忘记用第二个引号关闭它。
问题基本上是:
Close the string with a double-quote before the semi-colon.
The string should be enclosed in quote-marks, but you only ever open the string, forgetting to close it with the second quote-mark.
The problem is basically: