更新时间:2022-10-20 15:44:05
不接受裸日期值作为DateTime。使用LocalDate而不是LocalDateTime解决问题:
DateTimeFormatter formatter = DateTimeFormatter.ofPattern(yyyyMMdd);
LocalDate dt = LocalDate.parse(20140218,格式化程序);
I am simply trying to convert a date string into a DateTime object in Java 8. Upon running the following lines:
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyyMMdd");
LocalDateTime dt = LocalDateTime.parse("20140218", formatter);
I get the following error:
Exception in thread "main" java.time.format.DateTimeParseException:
Text '20140218' could not be parsed:
Unable to obtain LocalDateTime from TemporalAccessor:
{},ISO resolved to 2014-02-18 of type java.time.format.Parsed
at java.time.format.DateTimeFormatter.createError(DateTimeFormatter.java:1918)
at java.time.format.DateTimeFormatter.parse(DateTimeFormatter.java:1853)
at java.time.LocalDateTime.parse(LocalDateTime.java:492)
The syntax is identical to what has been suggested here, yet I am served with an exception. I am using JDK-8u25
.
It turns out Java does not accept a bare Date value as DateTime. Using LocalDate instead of LocalDateTime solves the issue:
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyyMMdd");
LocalDate dt = LocalDate.parse("20140218", formatter);
无法在 Java 8 中使用 DateTimeFormatter 和 ZonedDateTime 从 TemporalAccessor 获取 ZonedDateTime
无法使用 Java 8 中的 DateTimeFormatter 和 ZonedDateTime 从 TemporalAccessor 获取 ZonedDateTime
无法使用Java 8中的DateTimeFormatter和ZonedDateTime从TemporalAccessor获取ZonedDateTime
解析 LocalDateTime (Java 8) 时无法从 TemporalAccessor 获取 LocalDateTime