这完全正常：

  Map< Long，< List&lt ;为MyObject&GT;&GT; grouped = ticks.stream（）。collect（Collectors.groupingBy（obj  - > obj.getTime（）/ intervalLength））; 
 

此方法将为您提供一个地图，您可以在该地图上调用.values（）来获取列表列表第一个元素将包含obj.getTime（）从0到intervalLength的元素，只要有这样的元素。第二个将包含intervalLength到intervalLength * 2，依此类推

I want to group a List of Objects containing a time attribute into 5-Minute intervals, preferably using streams and collectors.

The only possible solution I found on *** is to calculate how many intervals (sublists) I need, add every object to every one of these Lists and filter out the ones that dont fit into the respective timeframe, which is not exactly a nice solution.

(You can find the Thread here: How to group elements of a List by elements of another in Java 8)

I thought of something similar to this:

List<MyObject> list = new ArrayList<MyObject>();
.......
List<List<MyObject>> grouped = list.stream().collect(Collectors.groupingBy(obj -> obj.getTime() / intervalLength));

This of course doenst work.

I hope that, with Java 8 & its features being used more and more, we can find a suting solution for such a Problem.

Regards, Claas M.

EDIT: In the End, I used @Harsh Poddar's solution and converted the Map into a List of Lists using

for(Map.Entry<Integer, List<MyObject>> entry:map.entrySet())
  list.add(entry.getValue());

Note: The List had to be sorted afterwards.

This works totally fine:

Map<Long,<List<MyObject>> grouped = ticks.stream().collect(Collectors.groupingBy(obj -> obj.getTime() / intervalLength));

This method will give you a map on which you may then call .values() to get the list of lists. First element will contain elements with obj.getTime() from 0 to intervalLength provided there were such elements. The second will contain from intervalLength to intervalLength*2 and so on