没有。 Go不会提供逻辑 异或运算符（即XOR over booleans）和 按位异或运算符仅适用于整数。

但是，独家OR 可以根据其他逻辑运算符进行重写。当重新评估表达式（X和Y）时，

  X xor Y  - > （X || Y）&& ！（X& Y）
 

或者，更像Jsor指出的那样微不足道，

  X xor Y  -   - > X！= Y 
 

Is there no XOR operator for booleans in golang?

I was trying to do something like b1^b2 but it said it wasn't defined for booleans.

There is not. Go does not provide a logical exclusive-OR operator (i.e. XOR over booleans) and the bitwise XOR operator applies only to integers.

However, an exclusive-OR can be rewritten in terms of other logical operators. When re-evaluation of the expressions (X and Y) is ignored,

X xor Y -> (X || Y) && !(X && Y)

Or, more trivially as Jsor pointed out,

X xor Y <-> X != Y