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如何创建Windows脚本唯一的输出文件名?

更新时间:2022-10-23 20:40:53

  ::做出临时文件
:maketemp
SET临时文件=%TEMP%\\%随机%
如果不存在%临时文件%*(GOTO maketemp)ELSE(ECHO方式>%临时文件%A)

您现在有任何数量的可用文件名。

%临时文件%A 存在并且是空的,但%临时文件%anythingelse 应可供使用。


  @ECHO OFF
SETLOCAL
SET基本名=文件名
SET / A outname = 0
:genloop
SET / A outname + = 1
如果不存在基本名称%%%outname%.TXTGOTO genloop
SEToutname =%基本名称%% outname%.TXTECHO%outname%GOTO:EOF

啊 - 递增每次运行的目标文件名。这应该做到这一点。它实际上不是创建一个文件 - 你需要创建文件%outname%每次把它增加...

(之间的空间%基本名称%%outname%是可选的,当然 - 如果需要,忽略它。)


编辑成包括 .TXT

I am trying to create a windows script that should generate this kind of filename everytime I run it: filename1, filename2, filename3 and so on. Here is what I have so far:

(
@echo off
wmic logicaldisk get size,freespace,caption
) > disk.txt

I hope you can help me. Thanks!!

:: make a tempfile
:maketemp
SET "tempfile=%temp%\%random%"
IF EXIST "%tempfile%*" (GOTO maketemp) ELSE (ECHO.>"%tempfile%a")

You now have any number of filenames available.

%tempfile%a exists and is empty, but %tempfile%anythingelse should be available for use.


@ECHO OFF
SETLOCAL
SET "basename=filename"
SET /a outname=0
:genloop
SET /a outname+=1
IF EXIST "%basename% %outname%.txt" GOTO genloop
SET "outname=%basename% %outname%.txt"

ECHO %outname%

GOTO :EOF

Ah - increment the destination filename on each run. This should do that. It's not actually creating a file - you'd need to create the file %outname% each time to have it increment...

(the space between %basename% and %outname% is optional, of course - omit it if desired.)


edited to include .txt