关系的语义看起来不正确。我认为它应该是这样的：

$ p $ 类Restaurant（db.Model）：
...

dishes = db.relationship（'Dish'，secondary = restaurant_dish，
backref = db.backref（'restaurants'））
$ p $然后，检索一家餐馆的所有菜肴，你可以这样做：

这应该产生一个查询，如：

  SELECT dish。* 
 FROM dish 
 WHERE 
 EXISTS（
 SELECT 1 
 FROM restaurant_dish 
 WHERE 
 dish.id = restaurant_dish.dish_id 
 AND EXISTS（
 SELECT 1 
 FROM餐馆
 WHERE 
 restaurant_dish.restaurant_id = restaurant.id 
 AND restaurant.name =：name 
）
）
 

I need help creating SqlAlchemy query.

I'm doing a Flask project where I'm using SqlAlchemy. I have created 3 tables: Restaurant, Dish and restaurant_dish in my models.py file.

restaurant_dish = db.Table('restaurant_dish',
    db.Column('dish_id', db.Integer, db.ForeignKey('dish.id')),
    db.Column('restaurant_id', db.Integer, db.ForeignKey('restaurant.id'))
)

class Restaurant(db.Model):
    id = db.Column(db.Integer, primary_key = True)
    name = db.Column(db.String(64), index = True)

    restaurant_dish = db.relationship('Dish', secondary=restaurant_dish,
        backref=db.backref('dishes', lazy='dynamic'))


class Dish(db.Model):
    id = db.Column(db.Integer, primary_key = True)
    name = db.Column(db.String(64), index = True)
    info = db.Column(db.String(256), index = True)

I have added data to the restaurant_dish table and it should be working correctly. Where I need help is understanding how to correctly get a Dish using Restaurant. Raw SQL would be something like this:

SELECT dish_id FROM restaurant_dish WHERE restaurant_id == id

What I have managed to get done but not working:

x = Restaurant.query.filter_by(Restaurant.restaurant_dish.contains(name)).all()

Thanks for help and I also appreciate tutorials that can point me in the right direction(the official documentation goes over my head).

The semantic of the relationship doesn't look right. I think it should be something like:

class Restaurant(db.Model):
    ...

    dishes = db.relationship('Dish', secondary=restaurant_dish,
        backref=db.backref('restaurants'))

Then, to retrieve all the dishes for a restaurant, you can do:

x = Dish.query.filter(Dish.restaurants.any(name=name)).all()

This should generate a query like:

SELECT dish.*
FROM dish
WHERE
    EXISTS (
        SELECT 1
        FROM restaurant_dish
        WHERE
            dish.id = restaurant_dish.dish_id
            AND EXISTS (
                SELECT 1
                FROM restaurant
                WHERE
                    restaurant_dish.restaurant_id = restaurant.id
                    AND restaurant.name = :name
            )
    )