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分享程序员开发的那些事...
且构网 - 分享程序员编程开发的那些事

在javascript中获取下拉列表选择的值

更新时间:2022-10-26 10:25:18

query = mysql_query( call prcSelectUsers ()跨度>);


while(


r = mysql_fetch_array(


query))
{
echo < option>

Hi i want to select options (single or multiple) from a dropdown list and then have to copy the selected options to another dropdown list. This is my coding.



<td>
 <select name="drpUsers" multiple="multiple" style="height:100;width:100">
 <?php
 	include "dbConnection.php";
	$query=mysql_query("call prcSelectUsers()");
	
	
	while($r=mysql_fetch_array($query))
	{
		echo "<option>".$r['vchUserName'];
		echo "</option>";
		
	}
  ?>
   
 </select>
 
 </td>



function add()
{
var b=document.getElementById('drpUsers').value;
alert(b);


}



This add() function is called in onclick of a button but variable b returns null how to do this? Pls help

query=mysql_query("call prcSelectUsers()"); while(


r=mysql_fetch_array(


query)) { echo "<option>".