Common Lisp通常不对表达式的第一个元素求值.它必须是为函数命名的文字符号或lambda表达式.

Common Lisp doesn't evaluate the first element of an expression normally. It has to be either a literal symbol naming a function, or a lambda expression.

如果要调用动态确定的函数，则需要使用

If you want to call a function determined dynamically, you need to use the FUNCALL function:

(funcall (if t 'format) t "test")

这类似于在Ruby中使用.call()方法的需要.

This is analogous to the need to use the .call() method in Ruby.

您尝试过的方法可以在其他Lisp方言中使用，例如Scheme.

What you tried would work in some other Lisp dialects, such as Scheme.