要在Drive上创建文件夹，请尝试：

To create a folder on Drive, try:

    def createRemoteFolder(self, folderName, parentID = None):
        # Create a folder on Drive, returns the newely created folders ID
        body = {
          'title': folderName,
          'mimeType': "application/vnd.google-apps.folder"
        }
        if parentID:
            body['parents'] = [{'id': parentID}]
        root_folder = drive_service.files().insert(body = body).execute()
        return root_folder['id']

如果您想在另一个文件夹中创建文件夹，则只需在此输入父ID，否则只是不要传递任何值。

You only need a parent ID here if you want to create folder within another folder, otherwise just don't pass any value for that.

如果您需要父级ID，则需要编写一种方法在该位置搜索具有该父级名称的文件夹（执行list（）调用）然后获取该文件夹的ID。

If you want the parent ID, you'll need to write a method to search Drive for folders with that parent name in that location (do a list() call) and then get the ID of that folder.

编辑：请注意，API的v3使用父母字段的列表，而不是字典。此外，'title'字段已更改为'name'， insert（） 方法更改为 create（）。从上面的代码将更改为以下v3：

Note that v3 of the API uses a list for the 'parents' field, instead of a dictionary. Also, the 'title' field changed to 'name', and the insert() method changed to create(). The code from above would change to the following for v3:

    def createRemoteFolder(self, folderName, parentID = None):
        # Create a folder on Drive, returns the newely created folders ID
        body = {
          'name': folderName,
          'mimeType': "application/vnd.google-apps.folder"
        }
        if parentID:
            body['parents'] = [parentID]
        root_folder = drive_service.files().create(body = body).execute()
        return root_folder['id']