它可能更简洁：

function power(base, exponent) {
  return exponent == 0? 1 : base * power(base, --exponent);
}

Howerver a 迭代解决方案速度非常快：

Howerver an iterative solution is very much faster:

function powerNR(base, exp) {
  var result = 1;
  while(exp--) {
    result *= base;
  }
  return result;
}