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如何通过Python中的字典值排序字典列表?

更新时间:2022-11-13 12:21:55

使用键而不是cmp看起来更清洁:



newlist = sorted(list_to_be_sorted,key = lambda k:k ['name'])

或JFSebastian等人建议,

  from operator import itemgetter 
newlist = sorted(list_to_be_sorted,key = itemgetter('name'))

为了完整性(如fitzgeraldsteele的评论中指出的),添加 reverse = True 排序降序

  newlist = sorted(l,key = itemgetter 'name'),reverse = True)


I got a list of dictionaries and want that to be sorted by a value of that dictionary.

This

[{'name':'Homer', 'age':39}, {'name':'Bart', 'age':10}]

sorted by name, should become

[{'name':'Bart', 'age':10}, {'name':'Homer', 'age':39}]

It may look cleaner using a key instead a cmp:

newlist = sorted(list_to_be_sorted, key=lambda k: k['name']) 

or as J.F.Sebastian and others suggested,

from operator import itemgetter
newlist = sorted(list_to_be_sorted, key=itemgetter('name')) 

For completeness (as pointed out in comments by fitzgeraldsteele), add reverse=True to sort descending

newlist = sorted(l, key=itemgetter('name'), reverse=True)