在以下code，让我假设使用空间boost 为简洁。结果
至于对字符分割，如果只算法/串是允许的，
is_from_range 可能达到目的：

In the following code, let me assume using namespace boost for brevity.
As for splitting on a character, if only algorithm/string is allowed, is_from_range might serve the purpose:

split(vec,str, is_from_range(':',':'));

另外，被允许如果的λ：

split(vec,str, lambda::_1 == ':');

如果preparing专用predicate是允许的：

or if preparing a dedicated predicate is allowed:

struct match_char {
  char c;
  match_char(char c) : c(c) {}
  bool operator()(char x) const { return x == c; }
};

split(vec,str, match_char(':'));

至于对一个字符串匹配，为的大卫Rodri'guez 的提到，
那里似乎不是与拆分的方式。
如果 iter_split 是允许的，可能是下面的code见面会的宗旨是：

As for matching against a string, as David Rodri'guez mentioned, there seems not to be the way with split. If iter_split is allowed, probably the following code will meet the purpose:

iter_split(vec,str, first_finder("::"));