更新时间:2022-11-25 19:54:23
尝试使用此查询脚本
var results = db.meta.aggregate([{
$project: {
id: "$_did",
_id: 0,
keys: "$metadata.id",
values: "$metadata.value"
}
}])
function object(keys, values) {
var obj = {};
for (var index in keys) {
obj[keys[index]] = values[index];
}
return obj;
}
results = results.map(function (res) {
return {
id: res.id,
metadata: object(res.keys, res.values)
}
})