如评论中所述，您应该能够执行以下操作（未经测试）将您的列表展平到一个字符向量中：

As mentioned in the comments, you should be able to do something like this (untested) to get "flatten" your list into a character vector:

output$Title <- vapply(output$Title, paste, collapse = ", ", character(1L))

也如前所述，如果您想尝试 unlist 方法，则可以通过 output $ Title ，类似这样：

As also mentioned, if you wanted to try the unlist approach, you could "expand" each row by the individual values in output$Title, something like this:

x <- vapply(output$Title, length, 1L)          ## How many items per list element
output <- output[rep(rownames(output), x), ]   ## Expand the data frame
output$Title <- unlist(output$Title, use.names = FALSE)  ## Replace with raw values