更新时间:2022-05-15 00:33:35
我建议将XSD文件的输出目录定义为目标/类(可能是一个补充子文件夹,它将是稍后在包装阶段打包到jar中。这可以通过使用 maven-resources来实现。 -plugin 。
I would suggest to define the output directory for the XSD files into target/classes (may be with a supplemental sub folder which will be packaged later during the package phase into the jar. This can be achieved by using the maven-resources-plugin.
<project>
...
<build>
<plugins>
<plugin>
<artifactId>maven-resources-plugin</artifactId>
<version>3.0.2</version>
<executions>
<execution>
<id>copy-resources</id>
<phase>process-classes</phase>
<goals>
<goal>copy-resources</goal>
</goals>
<configuration>
<outputDirectory>${project.build.outputDirectory}</outputDirectory>
<resources>
<resource>
<directory>${basedir}/target/xsd-out</directory>
<filtering>false</filtering>
</resource>
</resources>
</configuration>
</execution>
</executions>
</plugin>
</plugins>
...
</build>
...
</project>
您需要注意资源插件位于用于调用wsgen的插件之后部分。您也可以使用 prepare-package 阶段来确保资源正确打包。
You need to take care that the resources plugin is positioned after the plugin which is used to call the wsgen part. You can also use the prepare-package phase instead to make sure the resources will be correctly packaged.