更新时间:2022-12-09 14:48:14
您似乎要做的是使用SQL找到序列中的间隙。
如果我将数据复制为
What you appear to be trying to do is "find a gap in a sequence" using SQL.
If I replicate your data as
create table temp
(
ChNo int
)
insert into temp values (11),(12),(13),(15), (17),(20)
以下查询将返回
The following query will return
14<br />
SELECT TOP 1 ChNo + 1
FROM temp mo
WHERE NOT EXISTS
(
SELECT NULL
FROM temp mi
WHERE mi.ChNo = mo.ChNo + 1
)
ORDER BY
ChNo
根据接受的答案改编为这篇文章 [ ^ ]
其他解决方案将在这里讨论 [ ^ ]