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具有三个交叉表和多个列的SQL Pivot表动态

更新时间:2022-12-11 23:12:34

如果使用的是SQL Server 2005+,则可以使用几种方法来应用PIVOT函数.

If you are using SQL Server 2005+, then there are several ways that you can apply the PIVOT function.

您可以采用静态数据透视表的形式对值进行硬编码:

You can hard-code the values in the form of a static pivot:

select *
from
(
  select sname, 
    'hour_no_'+hr+'_'+convert(nvarchar(10), dt, 120) dt,
    att
  from stud
) st
pivot
(
  max(att)
  for dt in ([hour_no_1_2013-01-21], [hour_no_2_2013-01-21],
             [hour_no_1_2013-01-22], [hour_no_2_2013-01-22])
) piv

请参见带演示的SQL提琴

或者您可以在运行时使用动态sql生成sql语句.查询的动态版本为:

Or you can use dynamic sql to generate the sql statement at run-time. The dynamic version of the query is:

DECLARE @cols AS NVARCHAR(MAX),
    @query  AS NVARCHAR(MAX)

select @cols 
  = STUFF((SELECT ', ' + QUOTENAME('Hour_No_'+hr+'_'++convert(nvarchar(10), dt, 120)) 
           from stud
           group by hr, dt
           order by dt, hr
            FOR XML PATH(''), TYPE
            ).value('.', 'NVARCHAR(MAX)') 
        ,1,1,'')

set @query = 'SELECT sname,' + @cols + ' from 
             (
                select sname, 
                  ''hour_no_''+hr+''_''+convert(nvarchar(10), dt, 120) dt,
                  att
                from stud
            ) x
            pivot 
            (
                max(att)
                for dt in (' + @cols + ')
            ) p '

execute(@query)

请参见带演示的SQL小提琴.

两者都给出结果:

| SNAME | HOUR_NO_1_2013-01-21 | HOUR_NO_2_2013-01-21 | HOUR_NO_1_2013-01-22 | HOUR_NO_2_2013-01-22 |
-----------------------------------------------------------------------------------------------------
|   Abi |                    a |                    p |                   ml |                   od |
|  bala |                    p |                    a |                   od |                   ml |