更新时间:1970-01-01 07:57:54
重新思考你是如何做事的。
1 - 给你& LT; p为H.元素id。
2 - getElementById (the_id_you_set)。innerHTML ='coffee'
3 - 完成。
基本上适用于所有元素。
当你开始使用AJAX时,这变得至关重要。
var p = document.getElementsByTagName(p);
for(var i = 0; i< p.length; i ++){
if(p [i] .innerHTML ==Tea){
p [i] .innerHTML =牛奶;
休息;
}
}
< pre> var p = document.getElementsByTagName( p);
for(var i = 2; i< p.length; i ++){
if(p [i] .innerHTML ==Tea){
p [i] .innerHTML =咖啡;
休息;
}
}
I want to change the content of two p tags out of four p tags.
All of the the p tags are having same class.
I want to change the content by classname.
I tried using array of list elements.
What I have tried:
I tried for list.
<!DOCTYPE html>
Rethink how you do things.
1 - give your <p> elements id's.
2 - getElementById("the_id_you_set").innerHTML='coffee'
3 - done.
Works for essentially all elements.
When you start using AJAX, this becomes essential.
var p = document.getElementsByTagName("p"); for(var i=0;i<p.length; i++) { if(p[i].innerHTML == "Tea") { p[i].innerHTML = "Milk"; break; } }
<pre>var p = document.getElementsByTagName("p"); for(var i=2;i<p.length; i++) { if(p[i].innerHTML == "Tea") { p[i].innerHTML = "Coffee"; break; } }