分享程序员开发的那些事...
更新时间：2022-10-16 21:41:39
＆LT;脚本＆GT;
功能myFunction的（）{
变种X = document.getElementsByName（'口'）;
VAR rate_value;
对于（VAR I = 0; I＆LT; x.length;我++）{
如果（X [I] .checked）{
rate_value = X [I] .value的;
打破;
}
}
的document.getElementById（演示）的innerHTML = rate_value。 }
＆LT; / SCRIPT＆GT;
Am a bit stuck on where to go from here. I would like my radio button(s) to return the value of the selected button. But right now, its only return the value of the first item. How can I make it loop through all the values, here is my code.
<!DOCTYPE html>
<html>
<body>
<?php include 'db_connector.php';
$result = mysqli_query($con,"SELECT name FROM os_scope");
while($row = mysqli_fetch_array($result)) {
$row['name'];
echo "<input type='radio' name='os' value=".$row['name']." id='myRadio'>";
}
?>
<p>Click the "Try it" button to display the value of the radio button.</p>
<button onclick="myFunction()">Try it</button>
<p id="demo"></p>
<script>
function myFunction() {
var x = document.getElementById("myRadio").value;
document.getElementById("demo").innerHTML = x;
}
</script>
</body>
</html>
<script>
function myFunction() {
var x = document.getElementsByName('os');
var rate_value;
for(var i = 0; i < x.length; i++){
if(x[i].checked){
rate_value = x[i].value;
break;
}
}
document.getElementById("demo").innerHTML = rate_value;
}
</script>