更新时间:2023-01-09 21:31:16
为什么不定义自定义显示功能?
Why not define a custom display function?
例如
def display_path(path):
return path.replace("\", "/")
如果你想用 str.join
代替 os.path.join
,你可以这样做(str.join
期望单个列表,os.path.join
需要 *args
):
And if you want to substitute str.join
for os.path.join
, you can just do this (str.join
expects a single list, os.path.join
expects *args
):
join = lambda *args: "/".join(args)
也许更好的是让 Python 规范化所有内容,然后替换,例如:
Perhaps better would be to let Python normalize everything, then replace, e.g.:
join = lambda *args: os.path.join(*args).replace("\", "/")
当文件路径中有空格时,上述唯一的问题可能是在 posix 上.
The only issue with the above might be on posix when there is a space in the file path.
然后,您可以在 utils 文件的顶部放置一个 if
语句,并将 display_path
和 join
定义为无操作和os.path.join 如果不在 Windows 上.
You could then put an if
statement at the top of your utils file and define display_path
and join
as a no-op and as os.path.join respectively if not on Windows.