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分享程序员开发的那些事...
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解析Android中嵌套的JSON对象

更新时间:2023-01-12 10:58:22

好吧,我是个白痴。这个工程。

Ok, I'm an idiot. This works.

JSONObject businessObject = offerObject.getJSONObject("business");
String nameValue = businessObject.getString("name");
System.out.println(nameValue);

如果我只觉得两秒钟,然后再发布... JEES!

If I would only think for two seconds before posting... Jees!