（ ＃Panel ul li a）。find（ [value ='art6']）。parent（）。css（ 这里的样式）;

i想要访问A的父亲Li，并操纵它！

但它不起作用我怎么能这样做？



plz help！kquote>

在jQuery中， find（）方法是

获取当前每个元素的后代一组匹配的元素，由选择器，jQuery对象或元素过滤。



所以问题是你的第一个选择器一直到锚点本身，然后你的find（）正在寻找一个锚的后代。



改为这个它会起作用：

（＃Panel ul li）。find（a [value ='art6']）。parent（）。css（styles here）;

i have this code:

$("#Panel ul li a").find("[value='art6']").parent().css("styles here");

i want to access the Li , father of A , and manipulate it!
but it does not work how can i do that?

plz help!

("#Panel ul li a").find("[value='art6']").parent().css("styles here");

i want to access the Li , father of A , and manipulate it!
but it does not work how can i do that?

plz help!

In jQuery, the find() method is to
"Get the descendants of each element in the current set of matched elements, filtered by a selector, jQuery object, or element."

So the problem is that your first selector goes all the way down to the anchors themselves, then your find() is looking for a descendant of an anchor.

Change to this and it will work:

("#Panel ul li").find("a[value='art6']").parent().css("styles here");