更新时间:2023-01-17 19:24:19
这里有一个方法,返回带有特定注解的方法:
Here is a method, which returns methods with specific annotations:
public static List<Method> getMethodsAnnotatedWith(final Class<?> type, final Class<? extends Annotation> annotation) {
final List<Method> methods = new ArrayList<Method>();
Class<?> klass = type;
while (klass != Object.class) { // need to iterated thought hierarchy in order to retrieve methods from above the current instance
// iterate though the list of methods declared in the class represented by klass variable, and add those annotated with the specified annotation
for (final Method method : klass.getDeclaredMethods()) {
if (method.isAnnotationPresent(annotation)) {
Annotation annotInstance = method.getAnnotation(annotation);
// TODO process annotInstance
methods.add(method);
}
}
// move to the upper class in the hierarchy in search for more methods
klass = klass.getSuperclass();
}
return methods;
}
它可以根据您的特定需求轻松修改.请注意,提供的方法遍历类层次结构以查找具有所需注释的方法.
It can be easily modified to your specific needs. Pls note that the provided method traverses class hierarchy in order to find methods with required annotations.
这里有一种方法可以满足您的特定需求:
Here is a method for your specific needs:
public static List<Method> getMethodsAnnotatedWithMethodXY(final Class<?> type) {
final List<Method> methods = new ArrayList<Method>();
Class<?> klass = type;
while (klass != Object.class) { // need to iterated thought hierarchy in order to retrieve methods from above the current instance
// iterate though the list of methods declared in the class represented by klass variable, and add those annotated with the specified annotation
for (final Method method : klass.getDeclaredMethods()) {
if (method.isAnnotationPresent(MethodXY.class)) {
MethodXY annotInstance = method.getAnnotation(MethodXY.class);
if (annotInstance.x() == 3 && annotInstance.y() == 2) {
methods.add(method);
}
}
}
// move to the upper class in the hierarchy in search for more methods
klass = klass.getSuperclass();
}
return methods;
}
对于找到的方法的调用,请参考教程.这里的潜在困难之一是方法参数的数量,这可能因找到的方法而异,因此需要一些额外的处理.
For invocation of the found method(s) pls refer a tutorial. One of the potential difficulties here is the number of method arguments, which could vary between found methods and thus requiring some additional processing.