如果您想使用子集，您可以尝试：

$ b （df，！duplicateated（subset（df，select = c（allrl，RAW.PVAL））））
＃RAW.PVAL GR allrl Bak
＃1 0.05 fr EN1 B12
＃3 0.45 fr EN2 B10
＃4 0.35 fg EN2 B066

但是，我认为@ thelatemail的方法会更好

  df [！duplicateated（df [c（RAW.PVAL，allrl）]）] 
 

I would like to delete duplicate rows based in two collumns, instead just one.

My input df:

RAW.PVAL  GR     allrl  Bak
0.05      fr     EN1    B12
0.05      fg     EN1    B11
0.45      fr     EN2    B10
0.35      fg     EN2    B066

My output:

RAW.PVAL  GR  allrl   Bak
0.05      fr   EN1    B12
0.45      fg   EN2    B10
0.35      fg   EN2    B066

I had tried df<- subset(df, !duplicated(allrl, RAW.PVAL)), but I do not work to delete rows with this two columns simultaneously duplicated.

Thank you!

If you want to use subset, you could try:

  subset(df, !duplicated(subset(df, select=c(allrl, RAW.PVAL))))
 # RAW.PVAL GR allrl  Bak
 #1     0.05 fr   EN1  B12
 #3     0.45 fr   EN2  B10
 #4     0.35 fg   EN2 B066

But, I think @thelatemail's approach would be better

  df[!duplicated(df[c("RAW.PVAL","allrl")]),]