我使用存储过程和递归函数解决了这个问题.代码如下所示.(实际上我希望它生成一个菜单xml，因此显示了菜单的代码.

I solved it using a stored procedure and a recursive function. code shown below. (actually I wanted this to generate a menu xml, so the code is shown for the menu.

    CREATE PROCEDURE [dbo].[usp_GetMenu]
    AS
    BEGIN
        SET NOCOUNT ON;

        SELECT  dbo.fnGetMenuItems(MenuId)
        FROM    dbo.Menu
        WHERE   ParentMenuId IS NULL
        FOR XML PATH('MenuItems')
    END
    GO

CREATE FUNCTION [dbo].[fnGetMenuItems]
(
    @MenuId int
)
RETURNS XML
WITH RETURNS NULL ON NULL INPUT
AS
BEGIN

    RETURN 
    (
        SELECT  MenuId AS "@Id"
                , [Name] AS "@Name"
                , [URL] AS "@URL"
                , [Key] AS "@Key"
                , [dbo].[fnGetMenuItems](MenuId)
        FROM    dbo.Menu
        WHERE   ParentMenuId = @MenuId
        FOR XML PATH('MenuItem'),TYPE
    )

END
GO