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使用SQL Server datetime计算在一个地方的总时间

更新时间:2023-02-05 12:32:09

p>您需要做的是计算实体花费时间的地点之间的日期差异,如下所示

  SELECT 
*
FROM MyTable

结果值

 开始时间结束时间位置ID EntityID 
2014-09-23 14:07:43 2014-09-23 16:07:43 2 2
2014-09-23 14:09:03 2014-09-23 20:09:03 3 2
2014-09-23 14:09:51 2014-09-23 21:09:51 8 2
2014-09-23 14:15:10 2014-09-23 21:15:10 8 3
2014-09-23 14:15:16 2014-09-23 17:15:16 8 3
2014-09-23 14:15:23 2014-09-23 22:15:23 4 3
2014-09-23 14:15:32 2014-09-23 15:15:32 5 3
2014-09-23 14:06:26 2014-09-23 14:06:26 1 2

使用以下查询获取所需的结果

  SELECT 
DATEDIFF(MINUTE,MIN(Starttime),MAX(Endtime))TotalTimeSpentInMinutes,
LocationID
FROM MyTable
WHERE EntityID = 2
GROUP BY LocationID

结果值为

 code> TotalTimeSpentInMinutes LocationID 
0 1
120 2
360 3
420 8


I am new to SQL and I was wondering if the following is even possible to achieve.

Using SQL Server 2012 I would like to find the total time a given entity has spent in one location in minutes. There are multiple entries for each entity as they may have gone in and out of a given location many times during the day, I just want to find the total time spent in minutes for all the time spent for a given location.

The table has two datetime columns that display Starttime and Endtime, along with location ID and Entity ID.

I have managed to find a way to work out the time difference between Starttime and Endtime for one event, but I want to sum for all those events in the location to be displayed as total time.

Please let me know if I need to give any more information

What you need to do is to calculate the date difference between the locations where the entity had spent time, as below

SELECT
*
FROM MyTable

Result Values

Starttime               Endtime                 LocationID  EntityID
2014-09-23 14:07:43     2014-09-23 16:07:43     2           2
2014-09-23 14:09:03     2014-09-23 20:09:03     3           2
2014-09-23 14:09:51     2014-09-23 21:09:51     8           2
2014-09-23 14:15:10     2014-09-23 21:15:10     8           3
2014-09-23 14:15:16     2014-09-23 17:15:16     8           3
2014-09-23 14:15:23     2014-09-23 22:15:23     4           3
2014-09-23 14:15:32     2014-09-23 15:15:32     5           3
2014-09-23 14:06:26     2014-09-23 14:06:26     1           2

Use the below query to get the desired result

SELECT
    DATEDIFF(MINUTE, MIN(Starttime), MAX(Endtime)) TotalTimeSpentInMinutes,
    LocationID
FROM MyTable
WHERE EntityID = 2
GROUP BY LocationID

Result values would be

TotalTimeSpentInMinutes LocationID
0                       1
120                     2
360                     3
420                     8