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如何从 msbuild 项目文件本身中使用不同的参数调用相同的 msbuild 目标两次

更新时间:2023-02-05 19:22:02

你应该能够生成一个 ItemGroup 包含 Dirs 和 % .

You should be able to generate an ItemGroup containing the Dirs and then % on that.

<ItemGroup>
    <Dirs Include="C:DirA;C:DirB">
</ItemGroup>
<Target Name="CopyFiles"
    Condition="Exists('%(Dirs)') AND '@(FilesToCopy)' != ''"
    Inputs="@(FilesToCopy)"
    Outputs="@(FilesToCopy -> '%(Dirs)%(Filename)%(Extension)')">
    <Copy SourceFiles="@(FilesToCopy)" DestinationFolder="%(Dirs)" />
</Target>

或者您可以进行 2 次显式调用:

Or you can do 2 explicit calls:

<Target Name="CopyFiles">
    <MsBuild Projects="$(MSBuildProjectFullPath)" Targets="CopyASetOfFiles" Properties="FilesToCopy=@(FilesToCopy);DestDir=$(DirA)" />
    <MsBuild Projects="$(MSBuildProjectFullPath)" Targets="CopyASetOfFiles" Properties="FilesToCopy=@(FilesToCopy);DestDir=$(DirB)" />
</Target>

<Target Name="CopyASetOfFiles"
    Condition="Exists('$(DestDir)') AND '@(FilesToCopy)' != ''"
    Inputs="@(FilesToCopy)"
    Outputs="@(FilesToCopy -> '$(DestDir)%(Filename)%(Extension)')">
    <Copy SourceFiles="@(FilesToCopy)" DestinationFolder="$(DestDir)" />
</Target>

我没有测试过任何一种语法,但对第二种语法相对更有信心.

I haven't tested either syntax, but am relatively more confident of the second.

(答案,如果有的话,在我桌子上的 Sayed Hashimi 书中 - 你必须等到第一个:

(The answer, if there is one, is in my Sayed Hashimi book on my desk - you'll have to wait until the first of:

  1. 拿书
  2. 我觉得无聊
  3. Sayed 找到了这篇文章并提出了一个经过测试的绝妙答案)