根据您的标准 - 322表示为3，2045为20 - 如何除以100然后用 trunc（）向0舍入。

Given your criteria -- that 322 is represented as 3 and 2045 is 20 -- how about dividing by 100 and then rounding towards 0 with trunc().

 time_24hr <- c(1404, 322, 1945, 1005, 945)
 trunc(time_24hr / 100)