更新时间:2023-02-06 19:24:03
让我们的第一个点坐标为P1 =(x1,y1),第二个点P2 =(x2,y2).
那么P1P2向量的长度是(如果可用,请使用Math.Hypot
函数)
Let's first point coordinates are P1=(x1,y1), second point P2=(x2,y2).
Then length of P1P2 vector is (use Math.Hypot
function if available)
Len = Sqrt((x2-x1)*(x2-x1) + (y2-y1)*(y2-y1))
归一化(单位长度)方向向量为
Normalized (unit-length) direction vector is
dx = (x2-x1) / Len
dy = (y2-y1) / Len
当P1P3和P1P2向量具有相同方向时的P3坐标:
P3 coordinates for case when P1P3 and P1P2 vectors have the same direction:
x3 = x1 + Distance * dx
y3 = y1 + Distance * dy
反方向:
x3 = x1 - Distance * dx
y3 = y1 - Distance * dy