我认为你是在这里优先查询，这只有在你的学校有优先考虑时才会有效（不太可能）。通过明确的排序来解决它： queryOrderedByKey（）。然后还要确保循环覆盖结果中的子元素，因为查询将返回一个列表，即使只有一个结果：

$ .queryEqualToValue（Random School Name）
.observeSingleEventOfType（。code $ database
.child（Schools）
.queryOrderedByKey值，withBlock {快照in
为snapshot.children中的childSnapshot {
print（snapshot）
}
}）
pre>

I am trying to execute a Firebase query and it doesn't seem to be working properly. I am trying to access the name of a School I have in the Firebase Database. The database looks like this:

Schools {

    Random School Name {

        schoolLocation: Random Location
        uid: random UUID

    }
}

If I use the following code to get the info of the "Random School Name", I get a snapshot of null:

databaseReference.child("Schools").queryEqualToValue("Random School Name").observeSingleEventOfType(.Value, withBlock: { (snapshot: FIRDataSnapshot) in

        print(snapshot)

    }) { (error: NSError) in

        self.displayError("Search Failed", message: "We couldn't search for that - \(error.code): \(error.localizedDescription)")

}

If I use this line of code, however, the query gives me the name of the school back, as I would expect. I want to be able to track if there is an error using observeSingleEventOfType:

let query = databaseReference.child("Schools").queryEqualToValue("Florida Institute of Technology")

print(query)

Why isn't this working?

I think you're querying by priority here, which will only work if your schools have a priority (highly unlikely).

If that is indeed the problem, solve it by being explicit about the ordering: queryOrderedByKey(). Then also be sure to loop over the children in the result, since a query will return a list, even if there's only one result:

databaseReference
    .child("Schools")
    .queryOrderedByKey()
    .queryEqualToValue("Random School Name")
    .observeSingleEventOfType(.Value, withBlock: { snapshot in
        for childSnapshot in snapshot.children {
            print(snapshot)
        }
    })