更新时间:2023-02-09 15:29:36
您将不得不使用Array.find
或Array.filter
或Array.forEach
.
由于值是数组,并且需要元素的位置,因此必须对其进行迭代.
Since you value is array and you need position of element, you will have to iterate over it.
var data = [{"name":"placeHolder","section":"right"},{"name":"Overview","section":"left"},{"name":"ByFunction","section":"left"},{"name":"Time","section":"left"},{"name":"allFit","section":"left"},{"name":"allbMatches","section":"left"},{"name":"allOffers","section":"left"},{"name":"allInterests","section":"left"},{"name":"allResponses","section":"left"},{"name":"divChanged","section":"right"}];
var index = -1;
var val = "allInterests"
var filteredObj = data.find(function(item, i){
if(item.name === val){
index = i;
return i;
}
});
console.log(index, filteredObj);
var data = [{"name":"placeHolder","section":"right"},{"name":"Overview","section":"left"},{"name":"ByFunction","section":"left"},{"name":"Time","section":"left"},{"name":"allFit","section":"left"},{"name":"allbMatches","section":"left"},{"name":"allOffers","section":"left"},{"name":"allInterests","section":"left"},{"name":"allResponses","section":"left"},{"name":"divChanged","section":"right"}];
var val = "allInterests"
var index = data.findIndex(function(item, i){
return item.name === val
});
console.log(index);
默认Array.indexOf()
将searchValue与当前元素而不是其属性匹配.您可以引用 Array.indexOf-polyfill 在MDN上
Default Array.indexOf()
will match searchValue to current element and not its properties. You can refer Array.indexOf - polyfill on MDN