有没有必要到这里涉及到一个字符串。只需复制到一个新的数组，它是一个字符比你输入数组短。使用此任务的方法是 Arrays.copyOf 。

There is no need for a String to get involved here. Just copy into a new array that is one char shorter than your input array. The method to use for this task is Arrays.copyOf.

原因你的输出是越野车是因为在Java字符串有无关空终止符。您code的第一行创建一个字符串，它的最后一个字符是空字符。

The reason your output is buggy is because strings in Java have nothing to do with null-terminators. Your first line of code creates a string whose last character is the null-character.

如果您有垃圾继空字符，你可以使用新的String（inputArray），然后找到空字符与字符串。的indexOf（'\\ 0'）和使用，在 String.substring 操作切出不需要的部分。然而，这将是简单还是（从时间/空间复杂度的角度），只是迭代这个数组找到空字符，然后用 Arrays.copyOf 与指数作为分界点。

If you have garbage following the null-char, you can use new String(inputArray), then find the null-char with String.indexOf('\0') and use that in a String.substring operation to cut out the unneeded part. However, it would be still simpler (from the time/space complexity perspective) to just iterate over the array to locate the null-char and then use Arrays.copyOf with that index as cutoff point.