8月27日下午1:55，Phat G5（G3） < nob ... @ noone.comwrote：

我正在为向Array类添加一个新方法而烦恼。它可以在FF中使用
罚款，但在Safari中则不行。我不知道在IE中。我还没有得到

远。


Array.prototype.find = function（item）{for（var i in this）

if（item == this（i）

别忘了手动将代码包装成大约70个字符到

允许自动换行。


IE经常混淆（）和[]，也许你发现Firefox尝试

来补贴（或者不......只是一个猜测。


尝试：


if（item == this [i]）

-

Rob

文章 11 ********************** @ r23g2000prd.googlegroups .com ，RobG在
rg***@iinet.net.au 上写道8 / 27/07 1:52 AM：

8月27日下午1点55分，Phat G5（G3）< nob ... @ noone .comwrote：

>我正在为向Array类添加一个新方法而烦恼。它在FF中工作得很好但在Safari中却没有。我不知道在IE中。我还没有得到它。

Array.prototype.find = function（item）{for（var i in this）
if（item == this（i） ）

别忘了手动将代码包装在大约70个字符处

允许自动换行。


IE经常让[]与[]混淆，也许你已经发现Firefox尝试

来补贴（或者不是......只是猜测）。


尝试：


if（item == this [i]）


-

Rob

这是我修复过的错误，在发送之前忘了发帖。抱歉。这里

是基本的关于我在做什么的想法。


Array.prototype.find = function（item）{for（var i in this）

if（item ==这[i]）

返回（true）

返回（false）;

};


var groups = new Array（0）;

var dials = x.form.getElementsByTagName（&quo t;输入）

for（var i in dials）

if（dials [i] .type ==" radio" &安培;&安培; ！groups.find（dials [i] .name））

groups = groups.concat（new Array（dials [i] .name））

我试图通过一个表单的无线电拨号，并创建一个

阵列只是收音机拨号组/名称，然后能够像theForm一样在

a时解析组。元素[基团[I]] [j]的.checked。检查

组的输出会产生一个空数组。出于测试目的，我只采用了上面的

方法并进行了快速测试。


var x = new Array（" zz"）;

alert（x.find（" zz"））每次在Safari和IE6 + 7中都返回false，但在

Firefox中是真的。

它会出现原型寄存器，但它不会识别它自己的

属性，并且永远不会通过它们进行迭代，最终命中返回false。

从for ...更改循环到常规for循环没有区别。任何

其他建议？


谢谢


-S

8月27日上午6:45，Phat G5（G3） < nob ... @ noone.comwrote：

var x = new Array（" zz"）;

alert（x .find（" zz"））每次都在Safari和IE6 + 7中返回false，但在

Firefox中是真的。


它会出现原型寄存器但是它没有认识到它自己的

属性并且从不通过它们进行迭代并最终命中返回false。

从for..in循环变为a常规for循环没有区别。任何

其他建议？

嗯，是的：


1.使用[]，而不是Array构造函数。

2.永远不要使用for .. in语法迭代数组，

*尤其是*如果你正在扩展Array.prototype。使用传统的

代替（var i = 0，len = this.length; i< len; i ++）循环。

3.不要使用括号返回关键字。

4.总是用分号结束行。

5.如果你遇到循环和/或if语句的问题，请将
$ b包起来$ b他们的花括号{}。


通过JSLint运行你的代码（ http://www.jslint.com/lint.html ）

一些有启发性的建议。


因此，您的代码变为：


Array.prototype.find = function（item）{

for（var i = 0; i< this.length ; i ++）{

if（this [i] == item）{

返回true;

}

}

返回false;

};


这样测试[''a''，''b' '，''c'']。在IE中找到（''b''）=== true。


但更好的技巧是实现JS 1.6'的


if（typeof Array.prototype.indexOf！=''function''）{

Array.prototype.indexOf = function（item）{

// ..在这里实现

//参见 http://developer.mozilla.org/en/docs...:Array:indexOf

}

}


因为它已经存在于大多数浏览器中但是IE浏览器。


-David

I was toying around with adding a new method to the Array class. It works
fine in FF but not in Safari. I have no idea in IE. I have not gotten that
far yet.

Array.prototype.find = function(item) { for(var i in this )
if( item == this(i) )
return( true )
return( false );
};

Any suggestions?

Thanks, S

On Aug 27, 1:55 pm, "Phat G5 (G3)" <nob...@noone.comwrote:

I was toying around with adding a new method to the Array class. It works
fine in FF but not in Safari. I have no idea in IE. I have not gotten that
far yet.

Array.prototype.find = function(item) { for(var i in this )
if( item == this(i)

Don''t forget to manually wrap your code at about 70 characters to
allow for auto-wrapping.

IE often confuses () with [], maybe you have discovered Firefox trying
to make allowances for that (or not... just a guess).

Try:

if( item == this[i] )
--
Rob

in article 11**********************@r23g2000prd.googlegroups. com, RobG at
rg***@iinet.net.au wrote on 8/27/07 1:52 AM:

On Aug 27, 1:55 pm, "Phat G5 (G3)" <nob...@noone.comwrote:

>I was toying around with adding a new method to the Array class. It works
fine in FF but not in Safari. I have no idea in IE. I have not gotten that
far yet.

Array.prototype.find = function(item) { for(var i in this )
if( item == this(i)

Don''t forget to manually wrap your code at about 70 characters to
allow for auto-wrapping.

IE often confuses () with [], maybe you have discovered Firefox trying
to make allowances for that (or not... just a guess).

Try:

if( item == this[i] )
--
Rob

That was a typo I had fixed and forgot to post before sending. Sorry. Here
is a basic idea of what I was doing.

Array.prototype.find = function(item) { for( var i in this )
if( item == this[i] )
return( true )
return( false );
};

var groups = new Array(0);
var dials = x.form.getElementsByTagName("input")
for( var i in dials )
if( dials[i].type == "radio" && !groups.find(dials[i].name) )
groups = groups.concat(new Array(dials[i].name))
I was trying to go thru the radio dials of a form and create an array of
just the radio dial groups/names and then be able to parse the groups one at
a time like theForm.elements[groups[i]][j].checked. Checking the output of
groups yields an empty array. For testing purposes I just took the above
method and did a quick test.

var x = new Array("zz");
alert(x.find("zz")) returns false every time in Safari and IE6+7 but true in
Firefox.
It would appear the prototype registers but it''s not recognizing it''s own
attributes and never iterates thru them and ultimately hits return false.
Changing from a for..in loop to a regular for loop makes no difference. Any
other suggestions?

Thanks

-S

On Aug 27, 6:45 am, "Phat G5 (G3)" <nob...@noone.comwrote:

var x = new Array("zz");
alert(x.find("zz")) returns false every time in Safari and IE6+7 but true in
Firefox.

It would appear the prototype registers but it''s not recognizing it''s own
attributes and never iterates thru them and ultimately hits return false.
Changing from a for..in loop to a regular for loop makes no difference. Any
other suggestions?

Well, yes:

1. Use [], not the Array constructor.
2. Never, ever use the for .. in syntax to iterate through an Array,
*especially* if you''re extending Array.prototype. Use a conventional
for (var i=0, len=this.length; i<len; i++) loop instead.
3. Don''t use parentheses with the "return" keyword.
4. Always end lines in semicolons.
5. If you''re having trouble with loops and/or if statements, wrap
their blocks in curly braces {}.

Run your code through JSLint (http://www.jslint.com/lint.html) for
some enlightening suggestions.

Thus, your code becomes:

Array.prototype.find = function (item) {
for (var i=0; i<this.length; i++) {
if (this[i] == item) {
return true;
}
}
return false;
};

such that the test [''a'', ''b'', ''c''].find(''b'') === true in IE.

But a better technique would be to implement JS 1.6''s

if (typeof Array.prototype.indexOf != ''function'') {
Array.prototype.indexOf = function (item) {
// .. implementation here
// see http://developer.mozilla.org/en/docs...:Array:indexOf
}
}

as it''s already there on most every browser but IE.

-David