您要做的是将某个字符分割成字符串，在您的情况下，将其分隔为-"并保存将其放入数组并进行数组计数，请以您的反向方法传递每个元素..

例如.

What you have to do is split string for some character, in your case, its ''-'' and save it in array and for array count, pass each element in your reverse method..

For eg.

string s = "101-102-103-104-105";
   
    string[] numbers= s.Split('-');
    foreach (string num in numbers )
    {
       int a = Convert.ToInt16(num);
        int result=0;
     do
     {
         result = (result * 10) + (a% 10);
         a= a/ 10;
     }while (a> 0);
    
    Console.WriteLine(result);
    }

由于这是一个逻辑问题，我请您自己解决.您可以解决它，因为您可以解决一个问题.我给您一个窍门，将这个数字逻辑应用于3位数字的每个数字.只有当它为0时才需要对其进行自定义，否则在每种情况下都是相同的.您可以使用循环来做到这一点.
好吧，如果您尝试失败，那就看看吧.
http://wiki.answers.com/Q/Write_a_program_in_c_language_to_reverse_a_three_digit_with_ <.com _ blank new window> ^ ]

As it is a logical problem i refer you to do it by yourself.you can solve it as you can do it for one number.i give you one trick,apply this one number logic to every number of a 3 digit number.only you need to customize it when it is 0 otherwise for every case it is same.You can use loop to do it.
Ok,if you fail in your try then see it..
http://wiki.answers.com/Q/Write_a_program_in_c_language_to_reverse_a_three_digit_integer_number_without_using_loops[^]

我找到了解决方案:D，但我没有从字符串中使用方法:D
我想要这个代码....

I found solution :D and i don''t use from string method :D
I want This code....

{
    int a = Convert.ToInt16(txt1.Text), b = Convert.ToInt16(txt2.Text);
    int r = 0,s=0;
    lblshow.Text = null;

    for (int i = a; i <= b; i++)
    {
        s = i;
        while (s > 10)
        {
            r = r * 10 + (s % 10);
            s = s / 10;
        }
        r = r * 10 + (s % 10);
        lblshow.Text += r + " , ";
        r = 0;
    }
}