分享程序员开发的那些事...
更新时间：2023-02-11 19:17:09
可以说，上面的PHP code在文件中，update.php。然后你可以用下面的code -
Lets say the above PHP code is in file, update.php. Then you can use the following code -
<head>
<script src="jquery.js"></script>
<script>
function UpdateRecord(id)
{
jQuery.ajax({
type: "POST",
url: "update.php",
data: 'id='+id,
cache: false,
success: function(response)
{
alert("Record successfully updated");
}
});
}
</script>
</head>
<body>
<input type="button" id="button_id" value="Update" onClick="UpdateRecord(1);">
</body>
只是通过有效身份证件在UpdateRecord功能。把你的PHP code。在update.php文件。只要是在一个更安全的一面，你的PHP code替换 $ VAR = @ $ _ GET ['身份证']; 与 $ VAR = @ $ _ POST ['身份证']; 和检查，如果这对你的作品
Just pass a valid id in the UpdateRecord function. Put your PHP code in update.php file. Just to be on a safer side, in your PHP code replace $var = @$_GET['id'] ; with $var = @$_POST['id'] ; and check if this works for you