在您的第一个函数中， mylist [0 :: n] 是 [1、3] ，因为 0 :: n 表示第一个元素为0，其他元素在第一个之后的第n 个元素中.正如Daniel所建议的，您可以使用 mylist [:: n] ，这意味着每第n个 个元素.

In your first function mylist[0::n] is [1, 3] because 0::n means first element is 0 and other elements are every nth element after first. As Daniel suggested you could use mylist[::n] which means every nth element.

在第二个函数中索引从0开始，而 0％0 为0，因此它不会复制第一个元素.第三个元素相同( 2％2 为0).因此，您需要做的只是 new_list = [如果索引(1 +％)％n！= 0，则为枚举(mylist)中索引的项目，

In your second function index is starting with 0 and 0 % 0 is 0, so it doesn't copy first element. It's same for third element (2 % 2 is 0). So all you need to do is new_list = [item for index, item in enumerate(mylist) if (index + 1) % n != 0]

提示:在此类函数中，您可能希望使用 return 而不是 print().

Tip: you may want to use return instead of print() in functions like these.