更新时间:2023-02-14 10:38:08
在方法DeserializeXmlNode
中,在第二个参数中指定根节点名称,如以下代码所示:
In method DeserializeXmlNode
specify the root node name in second parameter as shown in below code:
XmlDocument doc =
(XmlDocument)
Newtonsoft.Json.JsonConvert.DeserializeXmlNode(json, "rootNodeName");
// second parameter
尽管可以给出json字符串,但给出确切答案很容易.
Although if you can give json string then it would be easy to give exact answer.
参考链接:将JSON转换为XML