简单aporoach是将拉姆达粘成一个的std ::功能＆LT;无效（）＆GT; 这是什么地方保留。可能是在堆上分配的，只是由无效* 与服用回调实体注册引用。然后回调，简直是一个功能线这样的：

The simple aporoach is to stick the lambda into a std::function<void()> which is kept somewhere. Potentially it is allocated on the heap and merely referenced by the void* registered with the entity taking the callback. The callback would then simply be a function line this:

extern "C" void invoke_function(void* ptr) {
    (*static_cast<std::function<void()>*>(ptr))();
}

注意的std ::功能＆LT; S＆GT; 可容纳状态函数对象，例如，一个非空捕捉波长的职能。你可以注册一个回调是这样的：

Note that std::function<S> can hold function objects with state, e.g., lambda functions with a non-empty capture. You could register a callback like this:

register_callback(&invoke_function,
  new std::function<void()>([=](){ ... }));