我想知道这样做是否容易使用 XOM 库并试一试。

I was wondering whether it would be easy to do this with the XOM library and gave it a try.

结果很简单：

import nu.xom.*;

import java.io.File;
import java.io.IOException;

public class RemoveEmptyTags {

    public static void main(String[] args) throws IOException, ParsingException {
        Document document = new Builder().build(new File("original.xml"));
        handleNode(document.getRootElement());
        System.out.println(document.toXML()); // empty elements now removed
    }

    private static void handleNode(Node node) {
        if (node.getChildCount() == 0 && "".equals(node.getValue())) {
            node.getParent().removeChild(node);
            return;
        }
        // recurse the children
        for (int i = 0; i < node.getChildCount(); i++) { 
            handleNode(node.getChild(i));
        }
    }
}

这可能无法处理正确的所有角落案例，就像一个完全空的文件。如何处理空的但具有属性的元素？

This probably won't handle all corner cases properly, like a completely empty document. And what to do about elements that are otherwise empty but have attributes?

如果要保存带有属性的XML标记，我们可以在方法'handleNode'中添加以下内容检查：

If you want to save XML tags with attributes, we can add in the method 'handleNode' the following check:

... && ((Element) node).getAttributeCount() == 0) )

此外，如果xml有两个或多个空标签，一个接一个;这个递归方法不会删除所有空标记！

Also, if the xml has two or more empty tags, one after another; this recursive method doesn't remove all empty tags!

（这个答案是我评估XOM作为潜在的替换为dom4j 。）

(This answer is part of my evaluation of XOM as a potential replacement to dom4j.)