听起来好像需要将Interface Builder中控制器实例的标识（换句话说是类）设置为自定义子类。

It sounds as though you need to set the identity (in other words the class) of the controller instance in Interface Builder to your custom subclass.

顺便说一下，IB中没有公开 UITableView 的 tableView 属性，因为它本质上是一个sy 视图属性的nonym - 两个属性都引用相同的实例变量 _view 。 tableView 属性只是更强类型。

By the way, the tableView property of UITableView isn't ever exposed in IB, because it's essentially a synonym for the view property -- the two properties both refer to the same instance variable, _view. The tableView property simply is more strongly typed.

只是附注：按照惯例，Objective-C类名应该以大写字母开头，即 ProcessViewController ，而不是 processViewController 。

Just a side note: by convention, Objective-C class names should begin with a capital letter, i.e., ProcessViewController, not processViewController.