如果你知道你将有完全相同4列，那么你也可以使用这个嵌套的CTE版本：

If you know you will have exactly 4 columns, then you can also use this nested CTE version:

;with s1 (name, extra) as
(
  select left(data, charindex('/', data)-1), 
    substring(data, charindex('/', data) +1, len(data))
  from yourtable
),
s2 (name, surname, extra) as
(
  select name, 
    left(extra, charindex('/', extra)-1), 
    substring(extra, charindex('/', extra)+1, len(extra))
  from s1
),
s3 (name, surname, [character], company) as
(
  select name, 
    surname, 
    left(extra, charindex('/', extra)-1), 
    substring(extra, charindex('/', extra)+1, len(extra))
  from s2
)
select *
from s3;

请参阅 SQL拨弄演示

的结果是：

|  NAME | SURNAME | CHARACTER | COMPANY |
-----------------------------------------
| Peter |  Parker | Spiderman |  Marvel |
| Bruce |   Wayne |    Batman |      DC |

或者你也可以同时实现这会将数据再 PIVOT A CTE：

;with cte (item, data, colNum, rn) as
(
  select cast(left(data, charindex('/',data+'/')-1) as varchar(50)) item,
    stuff(data, 1, charindex('/',data+'/'), '') data,
    1 colNum,
    row_number() over(order by data) rn
  from yourtable
  union all
  select cast(left(data, charindex('/',data+'/')-1) as varchar(50)) ,
    stuff(data, 1, charindex('/',data+'/'), '') data,
    colNum+1, 
    rn
  from cte
  where data > ''
) 
select [1] as Name, 
  [2] as Surname, 
  [3] as [character], 
  [4] as company
from
(
  select item, colnum, rn
  from cte
) src
pivot
(
  max(item)
  for colnum in ([1], [2], [3], [4])
) piv

请参阅 SQL拨弄演示