更新时间:2023-02-21 13:23:49
如果定位到ES3(最常见且安全使用的javascript版本),则使用
If targeting ES3 (the version of javascript that is most common, and safe to use) then use
var arr = ['apple','avocado','banana','cherry'];
var filtered = (function(){
var filtered = [], i = arr.length;
while (i--) {
if (/^A/.test(arr[i])) {
filtered.push(arr[i]);
}
}
return filtered;
})();
alert(filtered.join());
但是如果您以ES5为目标,则可以使用
But if you are targeting ES5 then you can do it using
var filtered = arr.filter(function(item){
return /^A/.test(item);
});
alert(filtered.join());
如果需要,您可以通过使用
If you want to you can include the ES5 filter method in ES3 by using
if (!Array.prototype.filter) {
Array.prototype.filter = function(fun /*, thisp*/){
var len = this.length >>> 0;
if (typeof fun != "function")
throw new TypeError();
var res = [];
var thisp = arguments[1];
for (var i = 0; i < len; i++) {
if (i in this) {
var val = this[i]; // in case fun mutates this
if (fun.call(thisp, val, i, this))
res.push(val);
}
}
return res;
};
}
请参见 https://developer.mozilla.org/En/Core_JavaScript_1.5_Reference/Objects/Array/filter#Compatibility 了解更多信息.
更新 回答更新的问题
var filtered = (function(pattern){
var filtered = [], i = arr.length, re = new RegExp('^' + pattern);
while (i--) {
if (re.test(arr[i])) {
filtered.push(arr[i]);
}
}
return filtered;
})('A'); // A is the pattern
alert(filtered.join());