仅连接值，例如

The just concatenate the values, e.g.

ArrayList al = new ArrayList();
al.Add(5);
al.Add("foo");
al.Add(true);
string s="";
foreach (object o in al)
{
  s += o.ToString();
}

如果您有很多项目，请考虑使用 StringBuilder [

If you have many items please consider using the StringBuilder[^] class.

http://msdn.microsoft.com上的

好示例/en-us/library/ttw7t8t6(v=vs.80).aspx [

nice example on http://msdn.microsoft.com/en-us/library/ttw7t8t6(v=vs.80).aspx[^]

您可以在互联网上找到针对您案件的通用解决方案.

这是我发现的:

Hi,

You can find generic solution for your case on internet.

Here is what I found:

public static class ExtensionMethods 
{     
	// for generic interface IEnumerable<t>     
	public static string ToString<t>(this IEnumerable<t> source, string separator)     
	{         
		if (source == null)             
			throw new ArgumentException("Parameter source can not be null.");         

		if (string.IsNullOrEmpty(separator))             
			throw new ArgumentException("Parameter separator can not be null or empty.");         

		string[] array = source.Where(n => n != null).Select(n => n.ToString()).ToArray();         
		return string.Join(separator, array);
	}     

	// for interface IEnumerable     
	public static string ToString(this IEnumerable source, string separator)     
	{         
		if (source == null)             
			throw new ArgumentException("Parameter source can not be null.");         

		if (string.IsNullOrEmpty(separator))             
			throw new ArgumentException("Parameter separator can not be null or empty.");

		string[] array = source.Cast<object>().Where(n => n != null).Select(n => n.ToString()).ToArray();
		return string.Join(separator, array);    
	} 
}
</t></t></t>

使用此扩展方法的示例:

Example of using this extension method:

ArrayList myArrayList = new ArrayList();
myArrayList.Add("Item1");
myArrayList.Add("Item2");
myArrayList.Add("Item3");
myArrayList.Add("Item4");
myArrayList.Add("Item5");
	
string myListAsString = myArrayList.ToString("; ");

输出:
Item1；项目2；项目3；项目4； Item5

Output:
Item1; Item2; Item3; Item4; Item5