在文章< 3f *********************** @ news.xs4all.nl>中，Rick写道：

In article <3f***********************@news.xs4all.nl>, Rick wrote:

Hi,

This is probably simple byt when you never did pointers and being used to
luxery strings like in Delphi or Visual Basic, C can get though. What I''m
trying to do is to add chars to a string.

您是否调查了strcat（）和strncat（）？

-

Andreas K？h？ri

Did you investigate strcat() and strncat()?
--
Andreas K?h?ri

要添加，我认为result2会被result1以某种方式覆盖。当那些2

被初始化时，它们会自动获得一个内存地址，而且当我将结果添加到result1时，似乎

，结果2不会进一步移动。结果1

可能只获得1个字节的内存，因此在添加第二个字符时，它的数量为b
。结果2上的和contineus。


如果这是真的，那将是非常危险的，因为我可以覆盖程序中的大部分内容。通常你可以使用数组和malloc它们，但在我的情况下，我真的不知道结果有多大。在构建

结果字符串时，我需要至少1个子字符串用于其他东西，该字符串有

同样的问题，我无法计算它有多大，它必须动态增长

。怎么处理这个？


问候，

Rick

To add, I think result2 get''s overwritten by result1 somehow. When those 2
got initialized they get a memory adress automatically and it seems that
when I''m adding chars to result1, result2 won''t move further. Result1
probably only get 1 byte of memory so when adding the second char it''s "out
of bounds" and contineus on result2.

If this is true, that would be quiete dangerous because I could overwrite a
big part of the program. Normally you can use arrays and malloc them but in
my case, I really don''t know how big the result becomes. While building the
result string, I need at least 1 sub string for other stuff, that string has
the same problem, I can''t calculate how big it becomes, it has to grow
dynamically. How to handle this?

Greetings,
Rick

你的答案比光快！我只是试了但是同样的问题

（看到其他帖子，我解释了问题一点点）。或者

也许我使用的代码错了，这就是我用strncat做的：


char * res1 ="&quot ;;

char * res2 ="&quot ;;

strncat（res1，" a"，1）;

strncat（res1，" b"， 1）;

strncat（res1，" c"，1）;

strncat（res2，" 1"，1）;

strncat（res2，" 2"，1）;

strncat（res2，" 3"，1）;

printf（" result1％s \ n"，res1）;

printf（" result2％s \ n"，res2）;


结果：res1 =" abc" RES2 = QUOT; bc123&QUOT ;.当使用strcat时一样。


问候，

Rick

You answered faster than the light! I just tried it but the same problem
(see that other post where I explained the problem a little bit more). Or
maybe I am using the code wrong, this is what I did with strncat:

char *res1 = "";
char *res2 = "";
strncat( res1, "a",1 );
strncat( res1, "b",1 );
strncat( res1, "c",1 );
strncat( res2, "1",1 );
strncat( res2, "2",1 );
strncat( res2, "3",1 );
printf( "result1 %s\n",res1 );
printf( "result2 %s\n",res2 );

result : res1 = "abc" res2="bc123". When using strcat the same.

Greetings,
Rick