" Ramprasad A Padmanabhan" <我**** @ netcore.co.in>在消息中写道

新闻：3F *************** @netcore.co.in ...

"Ramprasad A Padmanabhan" <my****@netcore.co.in> wrote in message
news:3F***************@netcore.co.in...

你好，

任何人都可以告诉我在哪里可以找到一个可以解码网址的函数
编码的字符串

ram％40domain.tld ==> ra*@domain.tld

写一个，不是那个意思程序员正在？

剥离％，然后接下来的2个字符并将它们从

ascii-hex转换为ascii。

Write one, isn''t that what a programmer is being?
strip off the "%", then take the next 2 characters and convert them from
ascii-hex to ascii.

Ramprasad A Padmanabhan写道：

Ramprasad A Padmanabhan wrote:

您好，

任何人都可以告诉我在哪里可以找到一个可以解码网址的函数
编码的字符串

Hello,

Can anyone tell me where Can I find a function that can decode a url
encoded string

这是一个很常见的事情。做谷歌搜索cgi实用程序
用b写的



Brian Rodenborn

This is a very common thing. Do a google search for cgi utilities
written in C.

Brian Rodenborn

Ramprasad A Padmanabhan< my **** @ netcore.co.in>在消息中写道

新闻：3F *************** @netcore.co.in ...

Ramprasad A Padmanabhan <my****@netcore.co.in> wrote in message
news:3F***************@netcore.co.in...

你好，

任何人都可以告诉我在哪里可以找到一个可以解码网址的函数
编码的字符串

ram％40domain.tld ==> ra *@domain.tld

/ *（不包括错误检查）* /


#include< stdio.h>

#include< stdlib.h>

#include< string.h>


void cvt（char * dest，const char * src）

{

const char * p = src;

char code [3] = {0};

unsigned long ascii = 0;

char * end = NULL;


while（* p）

{

if（* p ==''％''）

{

memcpy（代码，++ p，2）;

ascii = strtoul（代码，& end，16）;

* dest ++ =（ char）ascii;

p + = 2;

}

else

* dest ++ = * p ++;

}

}


int main（）

{

char in [] =" ram％40domain.tld";

char out [sizeof in] = {0};

cvt（out，in）;

printf（" in ==％s\\\
out ==％s \ n"，in，out）;

返回0;

}


-Mike

/* (no error checking included) */

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

void cvt(char *dest, const char *src)
{
const char *p = src;
char code[3] = {0};
unsigned long ascii = 0;
char *end = NULL;

while(*p)
{
if(*p == ''%'')
{
memcpy(code, ++p, 2);
ascii = strtoul(code, &end, 16);
*dest++ = (char)ascii;
p += 2;
}
else
*dest++ = *p++;
}
}

int main()
{
char in[] = "ram%40domain.tld";
char out[sizeof in] = {0};
cvt(out, in);
printf("in == %s\nout == %s\n", in, out);
return 0;
}

-Mike