我今天早些时候使用正则表达式做了类似的事情： / p>

I did something similar in a question earlier today using regexes:

str = str.replace(/<title>[\s\S]*?<\/title>/, '<title>' + newTitle + '<\/title>');

应该找到并替换它。 [\s\S] *？意味着[包括空格和换行符的任何字符]任意次数，使星号不贪心，因此它会在找到< / title> 时停止（更快）。

That should find and replace it. [\s\S]*? means [any character including space and line breaks]any number of times, and the ? makes the asterisk "not greedy," so it will stop (more quickly) when it finds </title>.