可能最干净的事情是创建另一个产品表，并拥有多对多关系。 （见这里： https：// docs。 djangoproject.com/en/dev/topics/db/models/#many-to-many-relationships 。在文档中，他们使用了具有许多浇头的比萨饼的例子。）

Probably the cleanest thing to do would be to create another "Products" table and have a many-to-many relationship. (See here: https://docs.djangoproject.com/en/dev/topics/db/models/#many-to-many-relationships . In the docs they use the example of a pizza having many toppings.)

另一个选项是序列化您的bill_products。在这种情况下，您可以执行以下操作：

The other option would be to serialize your bill_products. In that case, you'd do something like:

bill_products = json.dumps([rand_products])

这将在for循环之外（尽管在上面的例子中，rand_products只是一个值，需要修复）。

This would be outside of the for loop (although, in your example above, rand_products is only a single value, so you'll need to fix that).