这是我想到的:

using System;
using System.Text.RegularExpressions;

public class Test
{

    public static void Main()
    {
        string s = @"Hello John these are the files you have to send us today: 
            C:\projects\orders20101130.docx also we would like you to send 
            C:\some\file.txt, C:\someother.file and d:\some file\with spaces.ext  

            Thank you";

        Extract(s);

    }

    private static readonly Regex rx = new Regex
        (@"[a-z]:\\(?:[^\\:]+\\)*((?:[^:\\]+)\.\w+)", RegexOptions.IgnoreCase);

    static void Extract(string text)
    {
        MatchCollection matches = rx.Matches(text);

        foreach (Match match in matches)
        {
            Console.WriteLine("'{0}'", match.Value);
        }
    }

}

产生:(请参见 ideone )

'C:\projects\orders20101130.docx', file: 'orders20101130.docx'
'C:\some\file.txt', file: 'file.txt'
'C:\someother.file', file: 'someother.file'
'd:\some file\with spaces.ext', file: 'with spaces.ext'

regex并不是非常健壮(它确实做了一些假设)，但它也适用于您的示例.

The regex is not extremely robust (it does make a few assumptions) but it worked for your examples as well.

如果使用<file>标记，则为程序的版本.将正则表达式和Extract更改为:

Here is a version of the program if you use <file> tags. Change the regex and Extract to:

private static readonly Regex rx = new Regex
    (@"<file>(.+?)</file>", RegexOptions.IgnoreCase);

static void Extract(string text)
{
    MatchCollection matches = rx.Matches(text);

    foreach (Match match in matches)
    {
        Console.WriteLine("'{0}'", match.Groups[1]);
    }
}

也可以在 ideone 上获得.