你应该能够使用非贪婪量词，特别是* ?.您可能需要以下内容：

You should be able to use non-greedy quantifiers, specifically *?. You're going to probably want the following:

Pattern MY_PATTERN = Pattern.compile("\\[(.*?)\\]");

这将为您提供一个与您的字符串匹配的模式，并将文本放在方括号中第一组。查看 Pattern API文档更多信息。

This will give you a pattern that will match your string and put the text within the square brackets in the first group. Have a look at the Pattern API Documentation for more information.

要提取字符串，您可以使用以下内容：

To extract the string, you could use something like the following:

Matcher m = MY_PATTERN.matcher("FOO[BAR]");
while (m.find()) {
    String s = m.group(1);
    // s now contains "BAR"
}